By Eisenhart L.P.

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**Thirteen Books of Euclid's Elements. Books X-XIII**

After learning either classics and arithmetic on the college of Cambridge, Sir Thomas Little Heath (1861-1940) used his time clear of his activity as a civil servant to submit many works as regards to old arithmetic, either renowned and educational. First released in 1926 because the moment variation of a 1908 unique, this e-book includes the 3rd and ultimate quantity of his three-volume English translation of the 13 books of Euclid's parts, protecting Books Ten to 13.

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1 that Oψ ∈ Qp which is the desired function. e. on T, then f H2 < ∞ and hence f can be written as IO — product of the inner function I and the outer function O. e. on T as well as |dζ| ζ +z log ψ(ζ) , z ∈ D, O(z) = exp 2π D ζ −z 32 Chapter 2. e. on T. Accordingly, sup ψ(z) w∈D ≤ D |f |(z) sup w∈D 2 D dm(z) (1 − |z|2 )2 dm(z) < ∞. (1 − |σw (z)|2 )p (1 − |z|2 )2 − exp log ψ 2 (z) 2 − |f (z)|2 (1 − |σw (z)|2 )p (ii) If f is a universal covering map of Ω, it can be seen from [Ne, p. 1 (vi). 3 Derivative-free Module via Berezin Transformation The hyperbolic distance between two points in D is given by dD (z1 , z2 ) = log 1 + |σz1 (z2 )| 1 − |σz1 (z2 )| 1 2 , z1 , z2 ∈ D.

1. 3. For p ∈ (0, 2) and f ∈ B let distB (f, Qp ) = inf{ f − g Qp }. Then distB (f, Qp ) ≈ inf > 0 : 1Ω (f ) (z)(1 B : g∈ − |z|2 )p−2 dm(z) ∈ CMp , where Ω (f ) = {z ∈ D : (1 − |z|2)|f (z)| ≥ } and 1E stands for the characteristic function of a set E. Proof. Because of f ∈ B, this function has the following integral representation: f (z) = f (0) + 1 π D (1 − |w|2 )f (w) dm(w) = f1 (z) + f2 (z), w(1 ¯ − wz) ¯ 2 where f1 (z) = f (0) + 1 π Ω (f ) and 1 π f2 (z) = D\Ω (f ) Note that |f1 (z)| ≤ f B D (1 − |w|2 )f (w) dm(w) w(1 ¯ − wz) ¯ 2 (1 − |w|2 )f (w) dm(w).

Accordingly, we can use the H¨ older inequality with q ∈ (0, 2] to obtain I(F ; q, q) ≤ I(F ; p, 2) as desired. 4. Mixture of Derivative and Quotient 39 Case 2: q ∈ (2, ∞). Note that if p − q + 2 ∈ (0, ∞) and r ∈ (0, 1), then the second inequality in (i) holds, namely, D |F (rz)|p−q |rF (rz)|q (1 − |z|2 )q−1 dm(z) T |F (rζ)|p |dζ|. Thus, by integration from r to 1 with respect to rdr, we obtain I(F ; p, q) I(F ; p, 0). To establish the opposite inequality, we observe 1 r log |z| r 1 dr ≈ (1 − |z|2 ) 1 + log 2 .