By Melvin Hausner

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MkPk. We have assumed that they uniquely determine a new mass-point mP, where m = m1 + · · · + mk and where P is their center of mass. We shall write mP = m1P1 + · · · + mkPk Thus m1P1 + · · · + mkPk is a shorthand way of writing, “The mass-point obtained when all of the masses of m1P1, . . ” We have seen in the examples that the center of mass can be obtained by taking the centers of two points at a time, and repeating the operation. Hence it is necessary to concern ourselves only with the center of mass of two mass-points.

Therefore, we simply assume m + n = 1, p + q = 1, and we have where we have taken the liberty of using the same letters m and p for the new coefficients. Our way of proceeding is: We have an expression for P already. We eliminate F from (14′) and (15′) and compare with (12). , not collinear). This was never algebraically stated and is considered in the next example. 3). We shall not often use the technique of this example because it is much more convenient to look at a picture (Fig. 43). 6. EXAMPLE 3 (Equating coefficients).

Intuitively, we hardly expect different shades to be added to nQ to get mP. Since colors satisfy the (modified) axioms, we may adopt geometric language. For example, if R, Y, B are the three primary colors (assumed to exist), then a pure purple P is defined by 2P = 1R + 1B We may therefore speak of pure purple as the mid-point of red and blue. This brings us to the title of this section. We intend to paint a triangle with all possible colors (mixtures of R, Y and B). We start by painting the vertices R, Y, and B.